bip373
Read the manual to see if your question is answered there before posting. Many users will not reply if the answer is already available in the manual.
If your question is about troubleshooting, configuration, or tuning, you MUST include your processor type (MS-I or MS-II) and code version in your post. If your question is about PCB assembly or modifications, you must also include the main board version number (1.01, 2.2 or 3.0).
If you have questions about MS1/Extra or MS2/Extra code configuration or tuning, please post them at www.msextra.com Such questions posted here will be moved to: a temporary MSextra sub-forum, where they will be removed after 7 days
The full forum rules are here: Forum Rules, be sure to read them all regularly.
-
Bernard Fife
- Master Squirter
- Posts: 475
- Joined: Thu Oct 29, 2009 12:54 pm
Re: bip373
You only need the pull-up circuit with the 330 Ohm resistor if you are not controlling a coil directly. The manual says:
Note: If you are using the high current driver circuit to control an ignition module instead of a coil directly (and don't want to use the processor port directly - i.e., you have not jumpered JS10 to IGN), you likely need to to add a pull-up resistor. This allows the signal to go both high and low, rather than floating and low).....
Since you say you will be controlling a coil, you don't need the pull-up circuit or its resistor.
This is here: http://www.megamanual.com/ms2/V3assemble.htm#output
Lance.