Flex Fuel
Forum rules
Read the manual to see if your question is answered there before posting. Many users will not reply if the answer is already available in the manual.
If your question is about troubleshooting, configuration, or tuning, you MUST include your processor type (MS-I or MS-II) and code version in your post. If your question is about PCB assembly or modifications, you must also include the main board version number (1.01, 2.2 or 3.0).
If you have questions about MS1/Extra or MS2/Extra code configuration or tuning, please post them at www.msextra.com Such questions posted here will be moved to: a temporary MSextra sub-forum, where they will be removed after 7 days
The full forum rules are here: Forum Rules, be sure to read them all regularly.
Read the manual to see if your question is answered there before posting. Many users will not reply if the answer is already available in the manual.
If your question is about troubleshooting, configuration, or tuning, you MUST include your processor type (MS-I or MS-II) and code version in your post. If your question is about PCB assembly or modifications, you must also include the main board version number (1.01, 2.2 or 3.0).
If you have questions about MS1/Extra or MS2/Extra code configuration or tuning, please post them at www.msextra.com Such questions posted here will be moved to: a temporary MSextra sub-forum, where they will be removed after 7 days
The full forum rules are here: Forum Rules, be sure to read them all regularly.
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Bernard Fife
- Master Squirter
- Posts: 475
- Joined: Thu Oct 29, 2009 12:54 pm
Re: Flex Fuel
scnicholl,
Any commonly available watt (1/8, 1/6, 1/4, 1/2) resistor that is 10K Ohms will work. The resistor is there to limit the current supplied by a pull-up voltage. This pull-up is feed into a high impedance (think of it as high resistance) input and grounded by the sensor. When grounded, the current flow is small (I = V/R = ~5/10000 = 0.5 milliamps) and the power is minimal (P = IV = 0.0005*5 = 2.5 milliwatts).
Lance.
Any commonly available watt (1/8, 1/6, 1/4, 1/2) resistor that is 10K Ohms will work. The resistor is there to limit the current supplied by a pull-up voltage. This pull-up is feed into a high impedance (think of it as high resistance) input and grounded by the sensor. When grounded, the current flow is small (I = V/R = ~5/10000 = 0.5 milliamps) and the power is minimal (P = IV = 0.0005*5 = 2.5 milliwatts).
Lance.
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